Answer
$\frac{20}{9}$
Work Step by Step
$\frac{5}{2}$ $\times$ $\frac{2}{3}$ $\div$ (-$\frac{1}{4}$) $\div$ (-3)
RECALL:
$\frac{a}{b}$ $\div$ $\frac{c}{d}$ = $\frac{a}{b}$ $\times$ $\frac{d}{c}$
Use the rule above to obtain:
$\frac{5}{2}$ $\times$ $\frac{2}{3}$ $\times$ (-$\frac{4}{1}$) $\times$ (-$\frac{1}{3}$)
Multiply the numerators by each other, and multiply the denominators by each other:
$\frac{5\ \times\ 2\ \times\ (-4)\ \times\ (-1)}{2\ \times\ 3\ \times\ 1\ \times\ 3}$ =
Factor the numerator and the denominator:
$\frac{5\ \times\ 2\ \times\ (-1)\ \times\ 2\ \times\ 2\ \times\ (-1)}{2\ \times\ 3\ \times\ 1\ \times\ 3}$ =
Cancel the common factors in the numerator and the denominator to obtain:
$\frac{5\ \times\ 2\ \times\ 2 \times -1 \times -1}{3\ \times\ 3}$ =
$\frac{20}{9}$
