Answer
$\frac{20}{9}n$
Work Step by Step
We first apply the distributive property. Then, we simplify the resultant expression:
$n+\frac{4}{3}n-\frac{1}{9}n$
=$n(1+\frac{4}{3}-\frac{1}{9})$
=$n(\frac{1(9)+4(3)-1(1)}{9})$
=$n(\frac{9+12-1}{9})$
=$n(\frac{21-1}{9})$
=$n(\frac{20}{9})$
=$\frac{20}{9}n$
