Answer
see graph
Work Step by Step
The given number, $
\sqrt{92}
,$ is between the perfect squares $
\sqrt{81}=9
$ and $
\sqrt{100}=10
.$ Hence, it is between the integers $
9
$ and $
10
.$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 1 - Introduction to Algebraic Expressions - 1.4 Positive and Negative Real Numbers - 1.4 Exercise Set - Page 35: 40
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