Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 59: 119

$-\dfrac{7}{6}$

The given expression, $ \dfrac{7}{10}\div\left( \dfrac{-3}{5} \right) $, simplifies to \begin{array}{l}\require{cancel} \dfrac{7}{10}\cdot\left( \dfrac{5}{-3} \right) \\\\= \dfrac{7(5)}{10(-3)} \\\\= \dfrac{7(\cancel{5})}{\cancel{5}\cdot2(-3)} \\\\= \dfrac{7}{-6} \\\\= -\dfrac{7}{6} .\end{array}