Answer
$\text{undefined}$
Work Step by Step
Substituting $
x
$ with $
2
$, then the given expression, $
\dfrac{x^2+2^x}{x^2-2^x}
$, evaluates to
\begin{array}{l}\require{cancel}
\dfrac{2^2+2^2}{2^2-2^2}
\\\\=
\dfrac{4+4}{4-4}
\\\\=
\dfrac{8}{0}
\\\\=
\text{undefined}
.\end{array}