Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Mid-Chapter Review - Mixed Review - Page 37: 15

Answer

$84=2\cdot2\cdot3\cdot7$

Work Step by Step

Firstly write $84$ in the form of any two numbers as follows. $84=2\cdot42$ Since $42$ is not a prime number. Now factorize $42$ in the form of any two numbers as follows. $84=2\cdot2\cdot21$ Since $21$ is not a prime number. Now factorize $21$ in the form of any two numbers as follows. $84=2\cdot2\cdot3\cdot7$ Since now every factor is a prime number. This is the required answer.
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