Answer
$x_1$=-1
$x_2$=-1
(-1,-1)
Work Step by Step
$\frac{x_1+4}{3}+\frac{x_2+1}{2}=1$
$3x_1-x_2=-2$
Expres $x_2$ in terms of $x_1$.
$x_2=2+3x_1$
Substitute for $x_2$ in the first equation.
$\frac{x_1+4}{3}+\frac{(2+3x_1)+1}{2}=1$ $\rightarrow$ Simplify.
$\frac{x_1+4}{3}+\frac{3+3x_1}{2}=1$ $\rightarrow$ Multiply by 6 to remove fractions.
$2(x_1+4)+3(3+3x_1)=6$ $\rightarrow$ Simplify.
$2x_1+8+9+9x_1=6$
$11x_1=-11$
$x_1=-1$
Substitute for $x_1$ and solve for $x_2$.
$3x_1-x_2=-2$
$3(-1)-x_2=-2$
$x_2=-1$
