Answer
The solution of the system of equations is $x=5$ and $y=2$.
The graph of the corresponding equations for each step is the same.
Thus, the corresponding equations in each step are equivalent.
The graph of this system of equations as follows:
Work Step by Step
Step 1: Write the system of equations in row-echelon form as follows:
$\begin{matrix}
x&-&4y&=-3\\
5x&-&6y&=13
\end{matrix}$
Step 2: Add $-5$ times of the first equation to the second equation to get a new second equation.
$\begin{matrix}
x&-&4y&=-3\\
&&14y&=28
\end{matrix}$
Step 3: Multiply the second equation by $\dfrac{1}{14}$.
$\begin{matrix}
x&-&4y&=-3\\
&&y&=2
\end{matrix}$
Step 4: Add $4$ times of the second equation to the first equation to get a new first equation.
$\begin{matrix}
x&&&=5\\
&&y&=2
\end{matrix}$
So, the solution of the system of equations is $x=5$ and $y=2$.
The graph of the corresponding equations for each step is the same.
Thus, the corresponding equations in each step are equivalent.
The graph of this system of equations as follows:
