Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.2 Gaussian Elimination and Gauss-Jordan Elimination - 1.2 Exercises - Page 23: 37

Answer

$$x=0, \quad y=2-4t, \quad z= t.$$

Work Step by Step

The augmented matrix is given by $$\left[ \begin {array}{cccc} 3&3&12&6\\ 1&1&4&2 \\ 2&5&20&10\\ -1&2&8&4 \end {array} \right] . $$ Adding the first row to $-3$ times the second row, adding $-2$ times the first row to $3$ times the third row, adding the first row to $3$ times the fourth row, we get $$\left[ \begin {array}{cccc} 3&3&12&6\\ 0&3&12&6 \\ 0&0&0&0\\ 0&0&0&0\end {array} \right]. $$ Now, the crossposting system is given by $$ \begin{align*} 3x+3y+12z&=6 \\ 3y+12z&=6. \end{align*} $$ The above system has the solution $$x=0, \quad y=2-4t, \quad z= t.$$
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