Answer
See below.
Work Step by Step
$T(e^x)=(e^x)'=e^x=1\cdot e^x$, thus we can indeed see that $1$ is an eigenvalue with the corresponding eigenvector of $e^x$.
You need to log in to continue
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.