Intermediate Algebra (12th Edition)

by Lial, Margaret L.; Hornsby, John; McGinnis, Terry

Published by Pearson

ISBN 10: 0321969359

ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 20: 16

Answer

$-\frac{7}{18}$

Work Step by Step

$-\frac{5}{6}+\frac{4}{9}=-\frac{5\times3}{6\times3}+\frac{4\times2}{9\times2}=-\frac{15}{18}+\frac{8}{18}$ $\frac{8}{18}-\frac{15}{18}=\frac{8}{18}+(-\frac{15}{18})=\frac{8+(-15)}{18}=\frac{-7}{18}=-\frac{7}{18}$

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