Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.4 - Properties of Real Numbers - R.4 Exercises - Page 38: 32

Answer

$9r-11$

Work Step by Step

The distributive property holds that $a(b+c)=ab+ac$ (for real numbers $a$, $b$, and $c$). We are given the expression $5(r-3)+6r-2r+4$. We can use the distributive property to simplify the terms in parentheses and combine like terms. $5(r-3)+6r-2r+4=(5\times r)+(5\times-3)+6r-2r+4=5r-15+6r-2r+4=(5+6-2)r+(-15+4)=(9)r+(-11)=9r-11$
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