Answer
Not a real number
Work Step by Step
We know that $\sqrt -16$ is not a real number, because there is no real number $a$ such that $a^{2}=-16$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Test - Chapter R Test - Page 41: 19
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