Answer
$\frac{(6-y)^{2}}{7}$ $\lt$ -2.
Work Step by Step
Translate this statement to symbols:
The square of the difference of 6 and y divided by 7 is less than -2.
The square of the difference of 6 and y
$(6-y)^{2}$
divided by 7
$\frac{(6-y)^{2}}{7}$
is less than -2.
$\frac{(6-y)^{2}}{7}$ $\lt$ -2
