Answer
$h=1$
Work Step by Step
We are given that $\frac{2+h}{9}+\frac{h-1}{3}=\frac{1}{3}$. First, we can multiply each term by 9. Since this is the least common denominator of each term, this will eliminate all fractions from the equation.
$\frac{2+h}{9}\times9+\frac{h-1}{3}\times9=\frac{1}{3}\times9$
$2+h+3\times(h-1)=3$
Use the distributive property to simplify the left side.
$2+h+3h-3=3$
Group like terms on the left side.
$4h-1=3$
Add 1 to both sides.
$4h=4$
Divide both sides by 4.
$h=1$
