Answer
$\approx 2.695$
Work Step by Step
The base of the logarithm is not $10$, therefore you require the change of base formula before evaluating:
$ \log_{25} (5860)$
$= \frac{\log 5860}{\log 25}$
$= 2.69532...$
$\approx 2.695$.
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises - Page 504: 50
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
