Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.2 - Operations with Real Numbers and Simplifying Algebraic Expressions - Exercise Set - Page 27: 91

Answer

$14$

Work Step by Step

According to the order of operations, we simplify inside parentheses, then we simplify powers, then we multiply and divide, and finally, we add and subtract. When we do this, we find: $=8-3[-2(-3)-4(2)] \\=8-3(6-8) \\=8-3(-2) \\=8-(-6) \\=8+6 \\=14$
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