Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.2 - Operations with Real Numbers and Simplifying Algebraic Expressions - Exercise Set - Page 29: 149

Answer

(a.)$1200-0.07x$. (b.)$\$780$.

Work Step by Step

The given equation for the total interest earned at the end of the year is $=0.05x+0.12(10,000-x)$ (a.) Apply distributive property. $=0.05x+0.12\times 10,000-0.12\times x$ Simplify. $=0.05x+1200-0.12x$ $=0.05x-0.12x+1200$ Apply distributive property. $=(0.05-0.12)x+1200$ Simplify. $=-0.07x+1200$ $=1200-0.07x$ (b.) From the question we have $x=\$6,000$. Plug the value of $x$ into the resultant from part (a.). $=1200-0.07(6,000)$ Clear the parentheses. $=1200-420$ $=\$780$.
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