Answer
if $x=-2$, $y=-\frac{1}{2}$ --> $(-2,-\frac{1}{2})$
if $x=-1$, $y=-\frac{1}{1}$ --> $(-1,-1)$
if $x=-\frac{1}{2}$, $y=-2$ --> $(-\frac{1}{2},-2)$
if $x=2$, $y=\frac{1}{2}$ --> $(2,\frac{1}{2})$
if $x=-\frac{1}{3}$, $y=-3$ --> $(-\frac{1}{3},-3)$
if $x=\frac{1}{3}$, $y=3$ --> $(\frac{1}{3},3)$
if $x=\frac{1}{2}$, $y=2$ --> $(\frac{1}{2},2)$
if $x=1$, $y=1$ --> $(1,1)$
if $x=2$, $y=\frac{1}{2}$ --> $(2,\frac{1}{2})$
Work Step by Step
$$y = \frac{1}{x}$$
(Let $x = -2, -1, -\frac{1}{2}, 2, -\frac{1}{3}, \frac{1}{3}, \frac{1}{2}, 1,$ and $2$.)
Substitute the values of $x$ to the equation:
if $x=-2$, $y=-\frac{1}{2}$ --> $(-2,-\frac{1}{2})$
if $x=-1$, $y=-\frac{1}{1}$ --> $(-1,-1)$
if $x=-\frac{1}{2}$, $y=-2$ --> $(-\frac{1}{2},-2)$
if $x=2$, $y=\frac{1}{2}$ --> $(2,\frac{1}{2})$
if $x=-\frac{1}{3}$, $y=-3$ --> $(-\frac{1}{3},-3)$
if $x=\frac{1}{3}$, $y=3$ --> $(\frac{1}{3},3)$
if $x=\frac{1}{2}$, $y=2$ --> $(\frac{1}{2},2)$
if $x=1$, $y=1$ --> $(1,1)$
if $x=2$, $y=\frac{1}{2}$ --> $(2,\frac{1}{2})$
