Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 51: 60

Answer

$$x=3$$

Work Step by Step

$$2^{3}-[4(5-3)^{3}]=-8x$$ Perform the operation inside the parentheses: $$(5-3) = 2$$ Substitute the value to the original equation: $$2^{3}-[4(2)^{3}]=-8x$$ To simplify the term $[4(2)^{3}]$, get the value of to raise to the 3rd power then multiply to 4. Thus, $$[4(2)^{3}] = [4(8)] = 32$$ Rewrite the equation: $$2^{3}-32=-8x$$ $$8-32=-8x$$ $$-24=-8x$$ Divide both sides by $-8$: $$3 = x$$ $or$ $$x = 3$$
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