Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 52: 73

Answer

The year is $ 2020 $

Work Step by Step

The given mathematical models is model $ 1 : $ $ C=442x+12,969 $ Where $ C $ is cost $ x $ years after $ 1990 $ of what cost $ \$10,000 $ in $ 1984 $. Given cost $ C(x) = \$26,229 $ plug into model $ 1 $ $ 26,229=442x+12,969 $ Simplify. $ 26,229-12,969= 442x $ $ 13533 = 442x $ $ \frac{13533}{442} = x $ $ 30.62 = x $ $ 31 = x $ The year is $ = 1990+31 = 2020 $
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