Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 67: 28

Answer

(a.)Births per day $=384,000$. Deaths per day $=156,000$. (b.) $83$ million. (c.) $4$ years.

Work Step by Step

Let the number of births $=A$. and the number of death $=B$. From the question we have $\Rightarrow A=2B+72$ thousand...... (1) (a.) Population increase in a signle day $=A-B$. thousand. From the question we have $A-B=228$ thousand.....(2) Plug the value of $A$ from equation (1) to equation (2). $\Rightarrow (2B+72)-B=228$ Simplify. $\Rightarrow 2B+72-B=228$ $\Rightarrow B+72=228$ Subtract $72$ from both sides. $\Rightarrow B+72-72=228-72$ Simplify. $\Rightarrow B=156$ Plug the value of $B$ into equation (1). $\Rightarrow A=2(156)+72$ Simplify. $\Rightarrow A=312+72$ $\Rightarrow A=384$ Hence, the number of births per day $=384,000$. The number of deaths per day $=156,000$. (b.) Population increase in a single day $=228$ thousand. Multiply the population increase per day by $365$. $=228\times 365$ $=83220$ thousands. $=83,220,000$ Rounded to the nearest million $=83$ million. (c.) From the part (b.) per year increase $=83$ million. Let the number years for the population increases by an amount greater than the entire U.S. population $320$ million $=t$. $t=\frac{320}{83}$ Simplify. $t=3.85542$ Rounded value. $t=4$ years.
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