Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 69: 97

Answer

$x=\frac{7}{3}$

Work Step by Step

$\frac{(2 + 4)^2 + (-1)^5}{12\div2\times3 - 3}$ Solve for the numerator: $(2 + 4)^2 + (-1)^5$ $= (6)^2-1$ $=36-1$ $=35$ Solve for the denominator: $12\div2\times3 - 3$ $=6\times3-3$ $=18-3$ $=15$ Thus, the equation is equal to $\frac{35}{15}$ or $\frac{7}{3}$.
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