Answer
See the explanation below.
Work Step by Step
As per the definition of square root property, $\sqrt x= \pm x$
Thus, the roots of $36$ are $\sqrt{36}= \pm 6$
Or, $6$ and $-6$
Since, $(6)^2=36$ and $(-6)^2=36$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 105
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