Answer
The point on the graph is $(2.9,0.85)$.
Work Step by Step
From exercise $51$, the values are:
Hang time $t=0.85$ seconds.
Vertical distance of jump $d=2.9$ feet.
The point on the graph is
$(d,t)=(2.9,0.85)$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 560: 54
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