Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Mid-Chapter Check Point - Page 55: 15

Answer

2$\frac{1}{18}$

Work Step by Step

5$\frac{2}{9}$-3$\frac{1}{6}$ (5-3)+($\frac{2}{9}$-$\frac{1}{6}$) 2+($\frac{4}{18}$-$\frac{3}{18}$) 2+$\frac{1}{18}$=2$\frac{1}{18}$
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