Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set - Page 30: 124

Answer

5$^\circ$ C

Work Step by Step

C=$\frac{5}{9}$(F-32) C=$\frac{5}{9}$(41-32) C=$\frac{5}{9}$(9) C=$\frac{5\times9}{9}=\frac{45}{9}=\frac{45\div9}{9\div9}$ C=5
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.