Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set - Page 32: 149

Answer

The answer can be seen in the image below.

Work Step by Step

For the first measure: $\frac{1}{4} + \frac{1}{4} + \frac{1}{8} + \frac{1}{8} = \frac{3}{4}$ For the second measure: $\frac{1}{4} + \frac{1}{4} + \frac{1}{4} = \frac{3}{4}$ For the third measure: $\frac{1}{4} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{3}{4}$ For the fourth measure: $\frac{1}{4} + \frac{1}{4} + \frac{1}{8} + \frac{1}{8} = \frac{3}{4}$ When adding fractions with different denominators, all you have to do is convert them into fractions with the a common denominator then add and simplify. For example, in the first measure $\frac{1}{4}$ becomes $\frac{2}{8}$. If we add $\frac{2}{8} + \frac{2}{8} + \frac{1}{8} + \frac{1}{8} $, it equals $\frac{6}{8}$. The simplified form of $\frac{6}{8}$ is equal to $\frac{3}{4}$.
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