Answer
False.
In general, $a+(bc)\neq(a+b)(a+c)$;
in words, addition can not be distributed over multiplication.
Work Step by Step
For the equality to be true, it must be true for all a,b,c.
Counterexample: a=1, b=2, c=0
LHS = $1+(2\cdot 0)=1$
RHS = $(1+2)(1+0)=3(1)=3$
so, the statement is false.
To make it true, replace $=$ with $\neq$.
False.
In general, $a+(bc)\neq(a+b)(a+c)$;
in words, addition can not be distributed over multiplication.
