Answer
$\displaystyle \frac{-20}{x}+\frac{3}{x}$,
simplifies to $\displaystyle \frac{-17}{x}$
Work Step by Step
the quotient of $-20$ and a number ... $\rightarrow$... $\displaystyle \frac{-20}{x}$
...which is increased by ... $\rightarrow \displaystyle \frac{-20}{x}+...$
.... the quotient of $3$ and a number$\quad\rightarrow \displaystyle \frac{-20}{x}+\frac{3}{x}.$
This simplifies, because the demominator is common, to,
$...=\displaystyle \frac{ -20+3}{x}$
... then, adding different signed numbers,
we keep the sign of $-20$, because it has the greater absolute value,
and subtract their absolute values:
$=\displaystyle \frac{-(20-3)}{x}$
$=\displaystyle \frac{-17}{x}$
