Introductory Algebra for College Students (7th Edition)

by Blitzer, Robert F.

Published by Pearson

ISBN 10: 0-13417-805-X

ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 498: 1

Answer

$\frac{4x-20}{9x+27}$

Work Step by Step

If there are no common factors that can be eliminated, multiply numerator by numerator and denominator by denominator. $\frac{4}{x+3}\times\frac{x-5}{9}=\frac{4(x-5)}{9(x+3)}=\frac{4x-20}{9x+27}$

Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.