Answer
$(0,1,0,0),(1,0,0,0)$.
Work Step by Step
Plugging in $t=0$ and $z=0$ into the third equation, we get $x+y=1$. Thus $x=0,y=1$ and $x=1,y=0$ satisfy that equation. Thus two points on the line of intersection are $(0,1,0,0),(1,0,0,0)$.
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