Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.10 Exercises - Page 88: 9

Answer

See explanation

Work Step by Step

The population movement problems in this section let the total population is constant, with no migration or immigration. The statement that "about $7 \%$ of the city's population moves to the suburbs" means that the rest of the city's population $(93 \%)$ remain in the city. This determines the entries in the first column of the migration matrix which concerns movement from the city. \[ \begin{array}{l} \text { From } \\ \text { City Suburbs To: } \\ {\left[\begin{array}{ccc} 0.93 & & \text {City} \\ 0.07 & \text {Suburbs} \end{array}\right.} \end{array} \] Likewise, if $5 \%$ of the suburban population moves to the city, then the other $95 \%$ remain in the suburbs. \[ M=\left[\begin{array}{ll} 0.93 & 0.05 \\ 0.07 & 0.95 \end{array}\right] \] This determines the second column of the migration matrix The difference equation is \[ x_{k+1}=M x_{k} \text { for } k=0,1,2, \ldots . \] Also, \[ \begin{array}{r} x_{0}=\left[\begin{array}{rr} 800,000 \\ 500,000 \end{array}\right] \\ x_{1}=M x_{0}=\left[\begin{array}{rr} 0.93 & 0.05 \\ 0.07 & 0.95 \end{array}\right]\left[\begin{array}{r} 800,000 \\ 500,000 \end{array}\right]=\left[\begin{array}{r} 769,000 \\ 531,000 \end{array}\right] \end{array} \] The population in 2016 (when $k=1$ ) \[ x_{2}=M x_{1}=\left[\begin{array}{cc} 0.93 & 0.05 \\ 0.07 & 0.95 \end{array}\right]\left[\begin{array}{c} 769,000 \\ 531,000 \end{array}\right]=\left[\begin{array}{c} 741,172 \\ 558,280 \end{array}\right] \] The population in 2002 (when $k=2$ )
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