Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - Supplementary Exercises - Page 91: 23

Answer

$a=\frac{4}{5}, b=-\frac{3}{5}$

Work Step by Step

Solve $\left[\begin{array}{cc}a & -b \\ b & a\end{array}\right]\left[\begin{array}{l}4 \\ 3\end{array}\right]=\left[\begin{array}{l}5 \\ 0\end{array}\right]$ $4 a-3 b=5$ $4 b+3 a=0$ Multiply first equation with 4 and second with 3 and add them $16 a-12 b+12 b+9 a=20$ $25 a=20$ $a=\frac{20}{25}=\frac{4}{5}$ $4 a-3 b=5$ $\frac{16}{5}-3 b=5$ $-3 b=\frac{25-16}{5}=\frac{9}{5}$ $b=-\frac{3}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.