Answer
See solution
Work Step by Step
Because there are fewer than n vectors, an n by k matrix whose columns are the vectors $v_1$ to $v_k$ cannot have a pivot in each row and thus does not span $R^n$ and are thus not a basis for $R^n$.
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 4 - Vector Spaces - 4.3 Exercises - Page 217: 29
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
