Answer
(a) $V = (6 − 2x)(5 − x)x ft^3$.
(b) $0 < x < 3$
(c) $3.57 ft ×3.79 ft ×1.21 ft$
Work Step by Step
(a) The base has sides $\frac{(10 − 2x)}{2}$ and $6 − 2x$, and the height is $x$, so $V = (6 − 2x)(5 − x)x ft^3$
(b) From the picture below we see that $x < 5$ and $2x < 6$, so $0 < x < 3$
(c) $3.57 ft ×3.79 ft ×1.21 ft$
