Answer
$-\frac{2}{5}$
Work Step by Step
$\lim\limits_{x \to 3} \frac{f(x)}{g(x)} = \frac{\lim\limits_{x \to 3}f(x)}{\lim\limits_{x \to 3}g(x)}$
$\lim\limits_{x \to 3} f(x) = f(3)$, because $f$ is continuous.
Using the given $f(3)=-2$ and $\lim\limits_{x \to 3} g(x) = 5$, we have:
$\lim\limits_{x \to 3} \frac{f(x)}{g(x)} = \frac{-2}{5}=-\frac{2}{5}$
