Answer
$$1$$
Work Step by Step
$\dfrac{dy}{dx}=\dfrac{dy/d \theta }{dx/d \theta }\\=\dfrac{r \cos \theta+\sin\theta \dfrac{dr}{ d \theta}}{- r \sin \theta+\cos\theta \dfrac{dr}{ d \theta}}$
Now,
$\dfrac{dy}{dx}=\dfrac{(1) \cos (\dfrac{\pi}{2})+\sin (\pi/2) (-1)}{(-1) \sin (\dfrac{\pi}{2})+\cos (\pi/2) (-1) }\\=1$