Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 5 - Applications Of The Definite Integral In Geometry, Science, And Engineering - 5.2 Volumes By Slicing; Disks And Washers - Exercises Set 5.2 - Page 362: 9

Answer

$\text{The volume is}$ \begin{align} V = \frac{32}{5} \end{align}

Work Step by Step

$\text{It is given that}$ \begin{align} f(x) = x^2; x = 0 \ and \ x = 2 \end{align} $\text{To find the volume, we have to find the area of the cross section.}$ $\text{It is given that the cross section is squre, therefore:}$ \begin{align} A(x) = f^2(x) \end{align} $\text{Thus, the volume is}$ \begin{align} V = \int_0^2 x^4 \ dx = \left[ \frac{x^5}{5} \right]_0^2 = \frac{32}{5} \end{align}
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