Answer
-$1$
Work Step by Step
$\int _{-1}^{2}[f(x)+2g(x)]$ $dx$ = $\int _{-1}^{2}f(x)$ $dx$ + $\int _{-1}^{2}2g(x)$ $dx$
= $5$ + $2(-3)$
= $5$ - $6$
= -$1$
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