Answer
Work done along the path C is zero.
Work Step by Step
The force field is perpendicular tho the motion of the particle at every point along the path C. so, work done $\int_C \textbf F \cdot \textbf{dr} =0$.
You need to log in to continue
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.