Answer
$ln(z)+2ln(z-1)$
Work Step by Step
Use the rule that $log(ab)=log(a)+log(b)$ to simplify the logarithm to $ln(z)+ln((z-1)^{2})$. Finally, use the rule that $log(x^{n})=nlog(x)$ to reduce the $ln((z-1)^{2})$ and reach $ln(z)+2ln(z-1).$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 325: 27
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