Answer
x-intercept at ($\frac{-3}{2}$,0)
y-intercept at (0,1)
Work Step by Step
Find Intercepts:
x-int
0=$\frac{2}{3}$x+1
x=$\frac{-3}{2}$
x-intercept at ($\frac{-3}{2}$,0)
y-int
y=y=$\frac{2}{3}$(0)x+1
y=1
y-intercept at (0,1)
Find Symmetry:
Substitute -x for x. If equation is equivalent, graph is symmetric to y-axis.
y=$\frac{2}{3}$(-x)+1
y=1-$\frac{2}{3}$x
Equations are not equivalent, so not symmetric to y-axis.
Substitute -y for y. If equation is equivalent, graph is symmetric to x-axis.
(-y)=$\frac{2}{3}$x+1
y=$\frac{-2}{3}$x-1
Equations are not equivalent, so not symmetric to x-axis.
Substitute -y for y and -x for x. If equation is equivalent, graph is symmetric to origin.
(-y)=$\frac{2}{3}$(-x)+1
y=$\frac{2}{3}$x-1
Equations are not equivalent, so not symmetric to origin.
