Calculus (3rd Edition)

by Rogawski, Jon; Adams, Colin

Published by W. H. Freeman

ISBN 10: 1464125260

ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.5 Work and Energy - Exercises - Page 316: 1

Answer

$$627.2 \ J.$$

Work Step by Step

First, we find the force ($F=ma$): $$(4\ kg)(9.8 \ m/s^2)=39.2 \ N.$$ Now we find the work ($W=Fd$): $$(39.2 \ N)(16 \ m)=627.2 \ J.$$

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