Answer
x $\ne$ $\pi$/4 + k$\pi$, where k is any integer.
Work Step by Step
We must have: 1 - tan x $\ne$ 0. So, tan x $\ne$ 1.
But, tan x = 1 for x = $\pi$/4 + k$\pi$, where k is any integer.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - 1.2 Mathematical Models: A Catalog of Essential Functions - 1.2 Exercises - Page 33: 6
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