Chapter 1 - Functions and Limits - 1.3 New Functions from Old Functions - 1.3 Exercises - Page 44: 42

$(f\circ g\circ h) (x)=\displaystyle \tan(\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})$

$(f\circ g\circ h) (x)=f[g(h(x))]$ $g(h(x))=g(\displaystyle \sqrt[3]{x})=\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1}$ $f[g(h(x))]=f(\displaystyle \frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})=\tan(\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})$