Answer
(a)4
(b)$x^{\frac{−4}{3}}$
Work Step by Step
a)$\frac{4^{−3}}{2^{−8}} = \frac{2^{−6}}{2^{−8}} = 2^{−6+8} =2^2=4$
(b)$\frac{1}{\sqrt[3] {x^4}} =x^{\frac{−4}{3}}$
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