Answer
$m$ gets increasingly equal to $m_{0}$
Work Step by Step
we replace $v$ with $c$ and the equation becomes: $m=\frac{m_{0}}{\sqrt (1-\frac{c^{2}}{c^{2}}}$.this expression can be simplified to $m=\frac{m_{0}}{1}$,hence $m=m_{0}$
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