Answer
False
Work Step by Step
Consider $u=\lt 1,0,0\gt$ and $v=\lt 0,1,0\gt$
Then $|u+v|=|\lt 1,1,0\gt|=(1^{2}+1^{2})=\sqrt 2$
and
$|u|+|v|=(1^{2}+0^{2}+0^{2})+(0^{2}+1^{2}+0^{2})=2$
Thus $\sqrt 2\ne 2$
Hence, the statement is false.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 12 - Vectors and the Geometry of Space - Review - True-False Quiz - Page 882: 2
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