Answer
$(0,0)$ and $(4,16)$
Work Step by Step
$y=x^{2}$
$y=-x^{2}+8x$
$x^{2}=-x^{2}+8x$
$2x^{2}-8x=0$
$2x(x-4)=0$
$x=0,4$
$y(0)=(0)^{2}=0$
$y(4)=(4)^{2}=16$
$(0,0)$ and $(4,16)$
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